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PWD009: Incorrect privatization in OpenMP parallel region

Issue

A variable is being incorrectly privatized in the OpenMP datascoping clauses.

Actions

Change the data scope of the variable from private to shared.

Relevance

Specifying an invalid scope for a variable may introduce race conditions and produce incorrect results. For instance, when a variable must be shared among threads but it is privatized instead.

Code example

C

In the following code, C is incorrectly privatized since the threads operate on non-overlapping positions of the array:

void example(int m, double *A, double *B, double *C) {
double temp;

#pragma omp parallel for default(none) private(i, temp, C) shared(A, B, m)
for (int i = 0; i < m; i++) {
temp = A[i] * B[i];
C[i] = C[i] + temp;
}
}

To fix this, C should be moved to a shared clause:

void example(int m, double *A, double *B, double *C) {
double temp;

#pragma omp parallel for default(none) private(i, temp) shared(A, B, C, m)
for (int i = 0; i < m; i++) {
temp = A[i] * B[i];
C[i] = C[i] + temp;
}
}

Fortran

In the following code, C is incorrectly privatized since the threads operate on non-overlapping positions of the array:

subroutine example(A, B, C)
real, intent(in) :: A(:), B(:)
real, intent(inout) :: C(:)
real :: temp
integer :: i

!$omp parallel do default(none) private(i, temp, C) shared(A, B)
do i = 1, size(C, 1)
temp = A(i) * B(i)
C(i) = C(i) + temp
end do
end subroutine example

To fix this, C should be moved to a shared clause:

subroutine example(A, B, C)
real, intent(in) :: A(:), B(:)
real, intent(inout) :: C(:)
real :: temp
integer :: i

!$omp parallel do default(none) private(i, temp) shared(A, B, C)
do i = 1, size(C, 1)
temp = A(i) * B(i)
C(i) = C(i) + temp
end do
end subroutine example

References