PWR019: Consider interchanging loops to favor vectorization by maximizing inner loop's trip count
Issue
Performance can be increased by using the highest possible trip count in the vectorized loop.
Actions
Interchange loops so that the loop with the highest trip count becomes the innermost loop.
Relevance
Vectorization takes advantage of having as high a trip count (ie. number of iterations) as possible. When loops are perfectly nested and they can be safely interchanged, making the loop with the highest trip count the innermost should increase vectorization performance.
If the loop interchange introduces non-sequential memory accesses, the runtime can get slower because of the inefficient memory access pattern.
Code example
C
The following code shows two nested loops, where the outer one has a larger trip count than the inner one:
for (int i = 0; i < n; i++) {
for (int j = margin; j < n - margin; j++) {
bb[i][j] = 0.0;
for (int k = -margin; k < margin; k++) {
bb[i][j] += aa[i][j + k];
}
}
}
The value of margin
is not known at compile time, but it is typically low. We
can increase the loop trip count of the innermost loop by performing loop
interchange. To do loop interchange, the loop over j
and the loop over k
need to be perfectly nested. We can make them perfectly nested by moving the
initialization bb[i][j] = 0.0
into a separate loop:
for (int i = 0; i < n; i++) {
for (int j = margin; j < n - margin; j++) {
bb[i][j] = 0.0;
}
for (int k = -margin; k < margin; k++) {
for (int j = margin; j < n - margin; j++) {
bb[i][j] += aa[i][j + k];
}
}
}
Fortran
The following code shows two nested loops, where the outer one has a larger trip count than the inner one:
do i = 1, n
do j = margin, n - margin
bb(i, j) = 0.0
do k = -margin, margin
bb(i, j) = bb(i, j) + aa(i, j + k)
end do
end do
end do
The value of margin
is not known at compile time, but it is typically low. We
can increase the loop trip count of the innermost loop by performing loop
interchange. To do loop interchange, the loop over j
and the loop over k
need to be perfectly nested. We can make them perfectly nested by moving the
initialization bb(i, j) = 0.0
into a separate loop:
do i = 1, n
do j = margin, n - margin
bb(i, j) = 0.0
end do
do k = -margin, margin
do j = margin, n - margin
bb(i, j) = bb(i, j) + aa(i, j + k)
end do
end do
end do